Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Jack mows the lawn in 3 hours. Jane mows the same yard in 4 hours. If they worked together how much time would it take them to mow the yard?

Sagot :

konrad509
[tex]\frac{1}{3}+\frac{1}{4}=\frac{1}{x}\\ \frac{4}{12}+\frac{3}{12}=\frac{1}{x}\\ \frac{7}{12}=\frac{1}{x}\\ 7x=12\\ x=\frac{12}{7}\hbox { h}=1\hbox{ h }42\hbox{ min } 51.43 \hbox{ s} [/tex]
AL2006
Jack mows 1/3 of the lawn each hour.
Jane mows 1/4 of the lawn each hour.

Working together, they mow (1/3 + 1/4) of the lawn each hour.

In order to add the fractions, you need a common denominator.
12 will work:

(1/3 lawn/hour + 1/4 lawn/hour) = (4/12 + 3/12) = 7/12 lawn/hour.

This rate of work produces 12/7 hour/lawn.

12/7 hour = 1 hour    42 minutes    51.4 seconds
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.