Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Pretty slow that train ;)
t=s/v
v=12 km/h=10/3 m/s
s=250+50=300 m
t=300/(10/3)
t=300*3/10
t=30*3
t=90 s=1.5 min
t=s/v
v=12 km/h=10/3 m/s
s=250+50=300 m
t=300/(10/3)
t=300*3/10
t=30*3
t=90 s=1.5 min
From the instant when the nose of the locomotive reaches the beginning of the
bridge, it has to travel the whole 250m to get to the other end of the bridge, and
then it has to travel another 50m to get the rest of the train off the bridge. So it
has to travel 300m to get everything it's pulling across the bridge.
Time = distance/speed = 300m / (12,000 m/hr) = 0.025 hour = 1 minute 30 sec
bridge, it has to travel the whole 250m to get to the other end of the bridge, and
then it has to travel another 50m to get the rest of the train off the bridge. So it
has to travel 300m to get everything it's pulling across the bridge.
Time = distance/speed = 300m / (12,000 m/hr) = 0.025 hour = 1 minute 30 sec
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.