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6^x+8=17^2x-2 can I have help

Sagot :

[tex]6^{x+8}=17^{2x-2}\ \ \ \ \ \ |both\ sides\ log_6\\\\log_66^{x+8}=log_617^{2x-2}\\\\x+8=(2x-2)log_617\\\\x+8=2xlog_617-2log_617\\\\x-2xlog_617=-2log_617-8\\\\x(1-2log_617)=-2log_617-8\ \ \ \ |divide\ both\ sides\ by\ (1-2log_617)\\\\x=\frac{-2log_617-8}{1-2log_617}\\\\x=\frac{-(log_617^2+8)}{-(log_617^2-1)}\\\\x=\frac{log_6289+8}{log_6289-1}[/tex]
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