Answered

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If 2+xi=(x+1)+i, what is the value of x

and can you please show me the breakdown?

Thanks!

Sagot :

[tex]2+xi=(x+1)+i\\\\xi-x=1+i-2\\\\x(i-1)=i-1\ \ \ \ /:(i-1)\\\\x=\frac{i-1}{i-1}\\\\x=1[/tex]
konrad509
[tex]2+xi=x+1+i\\ xi-x=-1+i\\ x(i-1)=-1+i\\ x=\frac{-1+i}{i-1}=\\x =\frac{i-1}{i-1}\\ x=1 [/tex]
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