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Find the circumference and area of the circle whose equation is
(x-9)^2 + (y-3)^2 = 64. Leave the answer in the terms of pi

Sagot :

[tex](x-9)^2+(y-3)^2=64\\\\center\ of\ the\ circle:(9;\ 3)\\\\radius:r=\sqrt{64}=8\\\\circumference:C_O=2\pi r\to C_O=2\pi\cdot8=16\pi\\\\area:A_O=\pi r^2\to A_O=\pi\cdot8^2=64\pi[/tex]
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