Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

find the vertex of the parabola
y= x^2-2x-1
vertex (?,?)

Sagot :

[tex]y=ax^2+bx+c\\\\vertex:(x_v;\ y_v)\\\\x_v=\frac{-b}{2a}\ and\ y_v=f(x_v)[/tex]


[tex]y=x^2-2x-1\\\\a=1;\ b=-2;\ c=-1\\\\x_v=\frac{-(-2)}{2\cdot1}=\frac{2}{2}=1\\\\y_v=1^2-2\cdot1-1=1-2-1=-2\\\\Answer:(1;-2)[/tex]
konrad509
[tex]y=a(x-h)^2+k \Rightarrow \hbox{vertex}=(h,k)\\\\ y=x^2-2x-1\\ y=x^2-2x+1-2\\ y=(x-1)^2-2 \Rightarrow \hbox{vertex}=(1,-2)[/tex]
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.