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factor completely
16x^2 + 24x + 9

Sagot :

konrad509
[tex] 16x^2 + 24x + 9 =\\ (4x+3)^2[/tex]
[tex]16x^2+24x+9=(4x)^2+2(4x)(3)+3^2=(4x+3)^2=(4x+3)(4x+3)[/tex]



[tex]16x^2+24x+9=16x^2+12x+12x+9=4x(4x+3)+3(4x+3)\\\\=(4x+3)(4x+3)[/tex]
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