Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
From Binomial Theorem (x-2y)³:
([tex] (\frac{3}{0}) x^{3}+( \frac{3}{1} ) x^{2} *(-2y)+( \frac{3}{2})x*( -2y)^{2} +( \frac{3}{3}) x^{0} (-2y)^{3} =[/tex][tex] \frac{3!}{0!3!} x^{3}- \frac{3!}{1!2!} x^{2} 2y- \frac{3!}{2!1!}x4 y^{2}- \frac{3!}{3!0!}8 y^{3} [/tex]=x³-6x²y-12xy²-8y³
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.