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Sagot :
[tex]The\ vertx\ form:y=a(x-h)^2+k\\where\ the\ coordinates\ of\ vertex\ are\ (h;\ k)\\\\-------------------------\\\\vertex:(0;-3)\\\\y=a(x-0)^2+(-3)=ax^2-3\\\\if\ a=1\ then\ y=x^2-3\leftarrow answer[/tex]
Answer: Third option is correct.
Step-by-step explanation:
Since we have given that
We need a parabola with a vertex at (0,-3)
If we select the equation:
[tex]y = x^2 - 3[/tex]
When we put x = 0, we get
[tex]y=0-3\\\\y=-3[/tex]
And similarly, when we put y = -3, we get
[tex]-3=x^2-3\\\\0=x^2\\\\x=0[/tex]
Hence, third option is correct.

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