Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

determine the equation of a circle having a diameter with endpoints at (12,-14) and(2,4)

Sagot :

luana
Center of a circle is a midpoint of line connecting two endpoints so center is:
(12,-14) (2,4) we divide those two points by two 
C(a,b)- center
C(a,b)=((12+2)/2),(-14+4)/2)=(7,-5)
Radius is the distance from the center to any point on the circle:
we take point (2,4)
r=[tex] \sqrt{ (7-2)^{2} + (-5-4)^{2} } = \sqrt{25+81} = \sqrt{106} [/tex]

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.