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Sagot :
[tex]The \ formula \ for \ the \ area \ of \ a \ rectangle \ is: \\\\A=l\cdot w\\ where \ l \ is \ the \ length, \ w \ is \ the \ width \\\\ w = 5 \feet , \\ diagonal: \ d= 8 \ feet \\ \\ apply \ the \ Pythagorean \ Theorem:[/tex]
[tex]d^2=w^2+l^2 \\ \\l^2=d^2-w^2\\\\l^2=8^2-5^2\\\\l^2=64-25\\\\l^2=39[/tex]
[tex]l=\sqrt{39}\\\\l \approx 6.244998 \ feet\\\\A= 6.244998 * 5= 31.22499\approx 31.23 \ feet^2[/tex]
[tex]d^2=w^2+l^2 \\ \\l^2=d^2-w^2\\\\l^2=8^2-5^2\\\\l^2=64-25\\\\l^2=39[/tex]
[tex]l=\sqrt{39}\\\\l \approx 6.244998 \ feet\\\\A= 6.244998 * 5= 31.22499\approx 31.23 \ feet^2[/tex]
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