Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
The equation is [tex]-0.25x^2-x+2=0[/tex]
The coordinates are [tex](\frac{-b}{2a};\frac{-\Delta}{4a})[/tex]
[tex]\Delta=b^2-4ac=1+2=3[/tex]
The coordinates, thus, are [tex](\frac{1}{-0.5};\frac{-1}{-1})=(-2;1)[/tex]
The coordinates are [tex](\frac{-b}{2a};\frac{-\Delta}{4a})[/tex]
[tex]\Delta=b^2-4ac=1+2=3[/tex]
The coordinates, thus, are [tex](\frac{1}{-0.5};\frac{-1}{-1})=(-2;1)[/tex]
Answer:
Option B is right.
Step-by-step explanation:
given is an equation of a parabola
[tex]-0.25x^2 =y-2\\y=-0.25x^2 +2[/tex]
[tex]-x^2 =4y-8[/tex]
Vertex is (0,2)
It is open down.
Axis of symmetry is x=0 or y axis
Hence focus will lie on axis of symmetry ie y axis.
THe parabola has -4a = -4
Hence a = 1
SO focus will lie inside the parabola on axis of symmetry with a distance of a units from the vertex.
i.e. focus would equal = (0,2-1) = (0,1)
Option B is right
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.