Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Find the 6th term in the expanded form of the equation (2x+y)^9

Sagot :

konrad509
[tex]T_r={n \choose r-1}a^{n-(r-1)}b^{r-1}\\ T_6={9 \choose 6-1}(2x)^{9-(6-1)}y^{6-1}\\ T_6={9 \choose 5}(2x)^4y^{5}\\ T_6=\frac{9!}{5!4!}16x^4y^{5}\\ T_6=\frac{6\cdot7\cdot8\cdot9}{2\cdot3\cdot4}16x^4y^{5}\\ T_6=7\cdot2\cdot9\cdot16x^4y^{5}\\ T_6=2016x^4y^5[/tex]
[tex]Use\ the\ Pascal's\ Triangle\ (look\ at\ the\ picture)\\\\6-th\ term\ of\ (2x+y)^9\ is\\\\ 126(2x)^4y^5=126\times16x^4y^5=2016x^4y^5[/tex]
View image Аноним
View image Аноним
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.