Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
[tex]\sqrt{96x^2y}=\sqrt{16\cdot6\cdot x^2\cdot y}=\sqrt{16}\cdot\sqrt6\cdot\sqrt{x^2}\cdot\sqrt{y}\\\\=4\cdot\sqrt6\cdot x\cdot\sqrt{y}=4x\sqrt{6y}[/tex]
========================================================
[tex]\left(x^4y^4\right)^\frac{1}{3}=\left(x^4\right)^\frac{1}{3}\left(y^4\right)^\frac{1}{3}=x^{4\cdot\frac{1}{3}}y^{4\cdot\frac{1}{3}}=x^\frac{4}{3}y^\frac{4}{3}=x^{1+\frac{1}{3}}y^{1+\frac{1}{3}}\\\\=x^1x^\frac{1}{3}y^1y^\frac{1}{3}=x\sqrt[3]{x}\cdot y\sqrt[3]y=xy\sqrt[3]{xy}[/tex]
========================================================
[tex]\left(x^4y^4\right)^\frac{1}{3}=\left(x^4\right)^\frac{1}{3}\left(y^4\right)^\frac{1}{3}=x^{4\cdot\frac{1}{3}}y^{4\cdot\frac{1}{3}}=x^\frac{4}{3}y^\frac{4}{3}=x^{1+\frac{1}{3}}y^{1+\frac{1}{3}}\\\\=x^1x^\frac{1}{3}y^1y^\frac{1}{3}=x\sqrt[3]{x}\cdot y\sqrt[3]y=xy\sqrt[3]{xy}[/tex]
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.