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Sagot :
[tex]7+4+3+9[/tex]
[tex]11+12[/tex]
[tex]23[/tex]
[tex] \frac{23}{23} - \frac{4}{23} [/tex]
[tex] \frac{23-4}{23} [/tex]
[tex] \frac{19}{23} [/tex] [tex]chance[/tex]
[tex]11+12[/tex]
[tex]23[/tex]
[tex] \frac{23}{23} - \frac{4}{23} [/tex]
[tex] \frac{23-4}{23} [/tex]
[tex] \frac{19}{23} [/tex] [tex]chance[/tex]
Answer:
Probability of not drawing a green marble is 19/23.
Step-by-step explanation:
A jar is containing 7 red, 3 white, and 9 blue marbles.
Then the probability to draw a green marble will be = Numbers of green marbles/ Total numbers of marbles of all colors
P(G) = 4/(7 + 4 + 3 + 9)
P(G) = 4/23
Now the probability of not drawing a green marble = 1 - probability of drawing a green ball
P = 1 - 4/23 = 19/23
Therefore answer is 19/23.
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