Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

What is the probability of not drawing a green marble from a jar containing 7 red, 4 green, 3 white, and 9 blue marbles?

Sagot :

iloveonedirection
[tex]7+4+3+9[/tex]
[tex]11+12[/tex]
[tex]23[/tex]

[tex] \frac{23}{23} - \frac{4}{23} [/tex]

[tex] \frac{23-4}{23} [/tex]

[tex] \frac{19}{23} [/tex] [tex]chance[/tex]

Answer:

Probability of not drawing a green marble is 19/23.

Step-by-step explanation:

A jar is containing 7 red, 3 white, and 9 blue marbles.

Then the probability to draw a green marble will be = Numbers of green marbles/ Total numbers of marbles of all colors

P(G) = 4/(7 + 4 + 3 + 9)

P(G) = 4/23

Now the probability of not drawing a green marble = 1 - probability of drawing a green ball

P = 1 - 4/23 = 19/23

Therefore answer is 19/23.

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.