At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Area of circle= πr²
r-radius
A1-area of table with diameter 9ft
A2-area of circle with diameter 14ft
d=2r
A1=π*(4,5)²=20,25π
A2=π*7²=49π
A2-A1=49π-20,25π=28,75π=90,275≈90ft²
r-radius
A1-area of table with diameter 9ft
A2-area of circle with diameter 14ft
d=2r
A1=π*(4,5)²=20,25π
A2=π*7²=49π
A2-A1=49π-20,25π=28,75π=90,275≈90ft²
[tex]Area \ of \ a \ Circle : \\ \\A= \pi r^2 \\ \\ diameter : \ d_{1}= 9 \ ft \\ radius : r_{1} =\frac{d_{1}}{2}=\frac{9}{2}=4.5 \ ft \\ \\ d_{2}= 14 \ ft \\ radius : r_{2} =\frac{d_{1}}{2} =\frac{14}{2}=7 \ ft \\ \\A_{1}= (4.5)^2 \pi=20,25 \ cdot 3.14 = 63.585 \ ft^2 \\ \\A_{2}= 7^2 \pi=49 \cdot 3.14 = 153.86 \ ft^2 \\ \\ A_{2}-A_{1}= 153.86 - 63.585 = 90.275 \approx 90 \ ft^2 [/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.