Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Area of circle= πr²
r-radius
A1-area of table with diameter 9ft
A2-area of circle with diameter 14ft
d=2r
A1=π*(4,5)²=20,25π
A2=π*7²=49π
A2-A1=49π-20,25π=28,75π=90,275≈90ft²
r-radius
A1-area of table with diameter 9ft
A2-area of circle with diameter 14ft
d=2r
A1=π*(4,5)²=20,25π
A2=π*7²=49π
A2-A1=49π-20,25π=28,75π=90,275≈90ft²
[tex]Area \ of \ a \ Circle : \\ \\A= \pi r^2 \\ \\ diameter : \ d_{1}= 9 \ ft \\ radius : r_{1} =\frac{d_{1}}{2}=\frac{9}{2}=4.5 \ ft \\ \\ d_{2}= 14 \ ft \\ radius : r_{2} =\frac{d_{1}}{2} =\frac{14}{2}=7 \ ft \\ \\A_{1}= (4.5)^2 \pi=20,25 \ cdot 3.14 = 63.585 \ ft^2 \\ \\A_{2}= 7^2 \pi=49 \cdot 3.14 = 153.86 \ ft^2 \\ \\ A_{2}-A_{1}= 153.86 - 63.585 = 90.275 \approx 90 \ ft^2 [/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.