At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Area of circle= πr²
r-radius
A1-area of table with diameter 9ft
A2-area of circle with diameter 14ft
d=2r
A1=π*(4,5)²=20,25π
A2=π*7²=49π
A2-A1=49π-20,25π=28,75π=90,275≈90ft²
r-radius
A1-area of table with diameter 9ft
A2-area of circle with diameter 14ft
d=2r
A1=π*(4,5)²=20,25π
A2=π*7²=49π
A2-A1=49π-20,25π=28,75π=90,275≈90ft²
[tex]Area \ of \ a \ Circle : \\ \\A= \pi r^2 \\ \\ diameter : \ d_{1}= 9 \ ft \\ radius : r_{1} =\frac{d_{1}}{2}=\frac{9}{2}=4.5 \ ft \\ \\ d_{2}= 14 \ ft \\ radius : r_{2} =\frac{d_{1}}{2} =\frac{14}{2}=7 \ ft \\ \\A_{1}= (4.5)^2 \pi=20,25 \ cdot 3.14 = 63.585 \ ft^2 \\ \\A_{2}= 7^2 \pi=49 \cdot 3.14 = 153.86 \ ft^2 \\ \\ A_{2}-A_{1}= 153.86 - 63.585 = 90.275 \approx 90 \ ft^2 [/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.