Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.




 log6 (x+1)− log6 x =log6 29 

Sagot :

[tex]log_6(x+1)-log_6x=log_629;\ D:x+1 > 0\ \wedge\ x > 0\Rightarrow x\in\mathbb{R^+}\\\\log_6\frac{x+1}{x}=log_629\iff\frac{x+1}{x}=29\\\\29x=x+1\\\\29x-x=1\\\\28x=1\ \ \ \ /:28\\\\x=\frac{1}{28}\in D\leftarrow solution[/tex]
konrad509
[tex]D:x+1>0 \wedge x>0\\ D:x>-1 \wedge x>0\\ D:x>0\\ \log_6(x+1)-\log_6 x=\log_6 29\\ \log_6(x+1)=\log_6 29+\log_6x\\ \log_6(x+1)=\log_6 29x\\ x+1=29x\\ 28x=1\\ x=\frac{1}{28}[/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.