Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.




 log6 (x+1)− log6 x =log6 29 

Sagot :

[tex]log_6(x+1)-log_6x=log_629;\ D:x+1 > 0\ \wedge\ x > 0\Rightarrow x\in\mathbb{R^+}\\\\log_6\frac{x+1}{x}=log_629\iff\frac{x+1}{x}=29\\\\29x=x+1\\\\29x-x=1\\\\28x=1\ \ \ \ /:28\\\\x=\frac{1}{28}\in D\leftarrow solution[/tex]
konrad509
[tex]D:x+1>0 \wedge x>0\\ D:x>-1 \wedge x>0\\ D:x>0\\ \log_6(x+1)-\log_6 x=\log_6 29\\ \log_6(x+1)=\log_6 29+\log_6x\\ \log_6(x+1)=\log_6 29x\\ x+1=29x\\ 28x=1\\ x=\frac{1}{28}[/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.