prove that [tex]cos 9x-cos 5x/sin17x-sin3x=-sin2x/cos10x[/tex]

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29-07-2014
Mathematics

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prove that [tex]cos 9x-cos 5x/sin17x-sin3x=-sin2x/cos10x[/tex]

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pepe11 pepe11 · Answer 1 · 2014-07-29T10:34:05-04:00

pepe11 pepe11

29-07-2014

cos9x - cos5x = -2sin2x.sin7x
sin17x - sin3x = 2sin7x.cos10x
so f(x) = [tex] \frac{-2sin2x.sin7x}{2sin7x.cos10x} [/tex] =[tex] \frac{-sin2x}{cos10x} [/tex]

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