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Sagot :
[tex]\left\{\begin{array}{ccc}\frac{3x-1}{2y}=1\\x+2y=7\end{array}\right\\\\\left\{\begin{array}{ccc}\frac{3x-1}{2y}=1\\2y=7-x\end{array}\right\\\\substitute:\\\\\frac{3x-1}{7-x}=1\iff3x-1=7-x\\\\3x+x=7+1\\4x=8\\x=2\\\\2y=7-2\\2y=5\\y=2.5\\\\Answer:D)\ y > x[/tex]
You have to solve the system of equations
for 'x' and 'y'. When you do that,
you discover that x=0.846 and y=3.076. So Y > X .
you discover that x=0.846 and y=3.076. So Y > X .
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