Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Solve by using the quadratic formula.
15x^2 - 1 = 2x

Sagot :

[tex]15x^2-1=2x\\\\15x^2-2x-1=0\\\\a=15;\ b=-2;\ c=-1\\\\\Delta=b^2-4ac\to\Delta=(-2)^2-4\cdot15\cdot(-1)=4+60=64\\\\x_1=\frac{-b-\sqrt\Delta}{2}a;\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{64}=8\\\\x_1=\frac{2-8}{2\cdot15}=\frac{-6}{30}=-\frac{1}{5};\ x_2=\frac{2+8}{2\cdot15}=\frac{10}{30}=\frac{1}{3}[/tex]
Lilith
[tex]15x^2 - 1 = 2x \\\\15x^2-2x - 1 = 0\\ \\a=15, \ \ b=-2 , \ \ c=-1 \\ \\\Delta =b^2-4ac = (-2)^2 -4\cdot 15 \cdot (-1) = 4+60=64 \\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-(-2)-\sqrt{64}}{2\cdot 15 }=\frac{ 2-8}{30}=\frac{-6}{30}=- \frac{1}{5}\\ \\x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-(-2)+\sqrt{64}}{2\cdot 15 }=\frac{ 2+8}{30}=\frac{10}{30}= \frac{1}{3} [/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.