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What is the derivative of: y=1/(x+1)+2?

Sagot :

AL2006
That derivative is    - 1 / (x + 1)²
[tex]y=\frac{1}{x+1}+2=(x+1)^{-1}+2\\\\y'=\left[(x+1)^{-1}+2\right]'=-(x+1)^{-1-1}=-(x+1)^{-2}=-\frac{1}{(x+1)^2}[/tex]
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