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Sagot :
Perimeter of the rectangle is 2*(80+125)=410
The rectangle having the biggest area given the same perimeter is a square. So we need to go "the other way" -- find the rectangle with larger side ratio. 200 m and 5 m is a good example.
The area of the first rectangle: [tex]80 m \times 125 m =10000 m^2[/tex]
The area of the second rectangle : [tex]200 m \times 5 m = 1000 m^2[/tex] (10 times smaller).
The rectangle having the biggest area given the same perimeter is a square. So we need to go "the other way" -- find the rectangle with larger side ratio. 200 m and 5 m is a good example.
The area of the first rectangle: [tex]80 m \times 125 m =10000 m^2[/tex]
The area of the second rectangle : [tex]200 m \times 5 m = 1000 m^2[/tex] (10 times smaller).
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