Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

The width of a rectangle is 12 cm less than the length. The perimeter is 156 cm. Find the width and length.

Sagot :

[tex]w-the\ width\\l-the\ length\\\\w=l-12\\\\the\ perimeter\ of\ rectangle:P=2(w+l)\ and\ P=156cm\\\\2(w+l)=156\to\ put\ w=l-12\ to\ equation:\\\\2(l-12+l)=156\\2(2l-12)=156\ \ \ \ |divide\ both\ sides\ by\ 2\\2l-12=78\ \ \ \ \ |add\ 12\ to\ both\ sides\\2l=90\ \ \ \ \ |divide\ both\ sides\ by\ 2\\l=45\\\\w=45-12=33\\\\Solution:the\ width\ equal\ 33cm\ and\ the\ length\ equal\ 45cm.[/tex]
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.