Answered

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How do I solve for x? X+6x=56

Sagot :

MattD
[tex]ax^2+bx+c=0[/tex]
[tex]x^2+6x=56[/tex]
[tex]x^2+6x-56=0[/tex]
a=1    b=6    c=-56
[tex]\Delta=b^2-4ac=6^2-4*1(-56)=36+224=260[/tex]
[tex]\sqrt{\Delta}=2\sqrt{65}[/tex]
[tex]x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-2\sqrt{65}}{2*1}=-3-\sqrt{65}[/tex]
[tex]x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+2\sqrt{65}}{2*1}=-3+\sqrt{65}[/tex]
x+6x=56

7x=56

x= 8

So, x is equal to 8
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