Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
a-length
b-width
perimeter of rectangular floor: 2a+2b=204
The length is two times the width: a=2b
2a + 2b = 204
2*2b + 2b = 204
6b = 204|:6
b = 34
a=2b=2*34=68
a=68->length
b=34->width
b-width
perimeter of rectangular floor: 2a+2b=204
The length is two times the width: a=2b
2a + 2b = 204
2*2b + 2b = 204
6b = 204|:6
b = 34
a=2b=2*34=68
a=68->length
b=34->width
Perimeter of a rectangle = 2(length + width)
Let width be x and length be 2x.
204 ft = 2(2x+x)
204 ft = 2(3x)
204 ft = 6x
204/6 = x
34 = x
therefore, width (x) = 34 ft
length (2x) = 2(34) = 68 ft
Let width be x and length be 2x.
204 ft = 2(2x+x)
204 ft = 2(3x)
204 ft = 6x
204/6 = x
34 = x
therefore, width (x) = 34 ft
length (2x) = 2(34) = 68 ft
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.