Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

The dimensions of a brick that weighs 25 N are 0.19 m × 0.07 m × 0.095 m. What pressure does the brick exert on the ground if it is resting on its largest face?

Sagot :

MattD
p - pressure [Pa] 
Fn - pressure force [N]
S - surface area [m²]
S = 0.19m*0.095=0.01805 [m²] (the two largest values ​​of bricks)
[tex]p=\frac{F_n}{S}=\frac{25N}{0.01805m^2}=1385[Pa][/tex]

Answer:

The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.

Explanation:

Given that,

Weight of brick = 25 N

The dimensions of a brick are 0.19 m × 0.07 m × 0.095 m.

The pressure of the brick exert on the ground if it is resting on its largest face.

So, The area of largest face of brick is

[tex]A = 0.19\times 0.095[/tex]

[tex]A= 0.01805\ m^2[/tex]

The pressure of the brick on the ground is

The pressure is the force upon area.

The formula of pressure is

[tex]P =\dfrac{F}{A}[/tex]

[tex]P=\dfrac{25}{0.01805}[/tex]

[tex]P = 1385.04\ Pa[/tex]

Hence, The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.