Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
p - pressure [Pa]
Fn - pressure force [N]
S - surface area [m²]
S = 0.19m*0.095=0.01805 [m²] (the two largest values of bricks)
[tex]p=\frac{F_n}{S}=\frac{25N}{0.01805m^2}=1385[Pa][/tex]
Fn - pressure force [N]
S - surface area [m²]
S = 0.19m*0.095=0.01805 [m²] (the two largest values of bricks)
[tex]p=\frac{F_n}{S}=\frac{25N}{0.01805m^2}=1385[Pa][/tex]
Answer:
The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.
Explanation:
Given that,
Weight of brick = 25 N
The dimensions of a brick are 0.19 m × 0.07 m × 0.095 m.
The pressure of the brick exert on the ground if it is resting on its largest face.
So, The area of largest face of brick is
[tex]A = 0.19\times 0.095[/tex]
[tex]A= 0.01805\ m^2[/tex]
The pressure of the brick on the ground is
The pressure is the force upon area.
The formula of pressure is
[tex]P =\dfrac{F}{A}[/tex]
[tex]P=\dfrac{25}{0.01805}[/tex]
[tex]P = 1385.04\ Pa[/tex]
Hence, The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.