Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

The dimensions of a brick that weighs 25 N are 0.19 m × 0.07 m × 0.095 m. What pressure does the brick exert on the ground if it is resting on its largest face?

Sagot :

MattD
p - pressure [Pa] 
Fn - pressure force [N]
S - surface area [m²]
S = 0.19m*0.095=0.01805 [m²] (the two largest values ​​of bricks)
[tex]p=\frac{F_n}{S}=\frac{25N}{0.01805m^2}=1385[Pa][/tex]

Answer:

The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.

Explanation:

Given that,

Weight of brick = 25 N

The dimensions of a brick are 0.19 m × 0.07 m × 0.095 m.

The pressure of the brick exert on the ground if it is resting on its largest face.

So, The area of largest face of brick is

[tex]A = 0.19\times 0.095[/tex]

[tex]A= 0.01805\ m^2[/tex]

The pressure of the brick on the ground is

The pressure is the force upon area.

The formula of pressure is

[tex]P =\dfrac{F}{A}[/tex]

[tex]P=\dfrac{25}{0.01805}[/tex]

[tex]P = 1385.04\ Pa[/tex]

Hence, The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.