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Sagot :
You won't have to graph these equations in order to solve them.
Ok, x+2y=6, therefore x=6-2y.
2x+4y=36, so plug the value x (in terms of y) right into this equation.
2(6-2y)+4y=36
12-4y+4y=36. 12 is not equal to 36 so the problem breaks down.
Ok, x+2y=6, therefore x=6-2y.
2x+4y=36, so plug the value x (in terms of y) right into this equation.
2(6-2y)+4y=36
12-4y+4y=36. 12 is not equal to 36 so the problem breaks down.
[tex]\left\{\begin{array}{ccc}x+2y=6\\2x+4y=36\end{array}\right\\====================\\\\x+2y=6\\y-intercept\ (x=0)\\0+2y=6\\2y=6\\y=3\to(0;\ 3)\\x-intercept\ (y=0)\\x+2(0)=6\\x=6\to(6;\ 0)\\-----------------[/tex]
[tex]2x+4y=36\\y-intercept\ (x=0)\\2(0)+4y=36\\4y=36\\y=9\to(0;\ 9)\\x-intercept\ (y=0)\\2x+4(0)=36\\2x=36\\x=18\to(18;\ 0)[/tex]
[tex]The\ graph\ on\ the\ picture.\\\\Th lines\ are\ parallel.\ Conclusion:NO\ SOLUTION[/tex]
[tex]2x+4y=36\\y-intercept\ (x=0)\\2(0)+4y=36\\4y=36\\y=9\to(0;\ 9)\\x-intercept\ (y=0)\\2x+4(0)=36\\2x=36\\x=18\to(18;\ 0)[/tex]
[tex]The\ graph\ on\ the\ picture.\\\\Th lines\ are\ parallel.\ Conclusion:NO\ SOLUTION[/tex]

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