leticiabarraza
Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

how do you solve this? pre calculus; (-0.008) ^2/3

Sagot :

[tex]a^\frac{m}{n}=\sqrt[n]{a^m}\\---------------\\\\(-0.008)^\frac{2}{3}=\sqrt[3]{(-0.008)^2}=\left(\sqrt[3]{-0.008}\right)^2=\left(-0.2\right)^2=0.04[/tex]
0.008 is actually 8/1000, therefore -0.008 is -8/1000.

[tex] ( \frac{-8}{1000} )^{ \frac{2}{3} } = \sqrt[3]{( \frac{-8}{1000})^{2} } = \sqrt[3]{ \frac{64}{1,000,000} }= \frac{4}{100}=0.04= \frac{2}{50}= \frac{1}{25} [/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.