Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

find the equation of a line in slope intercept form, passing through (2,5) and parallel to 2x+3y=-12

Sagot :

kate200468
[tex]2x+3y=-12\ \ \ \Rightarrow\ \ \ 3y=-2x-12\ \ \ \Rightarrow\ \ \ y=- \frac{2}{3} x-4\\\\y=mx+b\ \ ||\ \ y=- \frac{2}{3} x-4\ \ \ \Leftrightarrow\ \ \ m=-\frac{2}{3}\\\\the\ point\ slope\ form:\ y-y_1=m(x-x_1)\ \ \ and\ \ \ (x_1,y_1)=(2,5)\\\\y-5=-\frac{2}{3}(x-2) \ \ \Rightarrow\ \ \ y-5=-\frac{2}{3}x+\frac{4}{3}\ \ \ \Rightarrow\ \ \ y=-\frac{2}{3}x+5+1\frac{1}{3} \\\\the\ slope\ intercept\ form:\ \ \ y=-\frac{2}{3}x+6\frac{1}{3}\\\\ the\ slope:\ m=- \frac{2}{3},\ \ \ the\ intercept:\ b=6\frac{1}{3}[/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.