sincerelykate
Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

Sagot :

dhawandymps21
Okay so according to the formula PV=nRT
n=4
P=5.6 atm
V=12 L
R=0.08206 L atm mol-1 K-1
T=?
So, if you plug it in, you will get:-

T=PV/nR
T=(5.6 atm)(12 L)/(4 mol)(0.08206 L atm mol-1 K-1)
T=204.73 K

Hope I'm right! :)

Answer:

PV=nRT

Explanation:

T=PV/nR

P=5.6atm n= 4 mol V=12 L R =.082Latm/K mol

T= (5.6 atm)(12 L)/(4 mol)(.082Latm/K mol)

T = 205 K = -68 C

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.