Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

in the diagram AB bisects FAE. BF=5x and BE=x2+6. Solve for x.

Sagot :

[tex] If\ AB^{\to}\ bisects\ \angle FAE\ then\ m\angle BAF=m\angle BAE\\\\5x=x^2+6\\\\x^2-5x+6=0\\\\x^2-2x-3x+6=0\\\\x(x-2)-3(x-2)=0\\\\(x-2)(x-3)=0\iff x-2=0\ or\ x-3=0\\\\\boxed{x=2\ or\ x=3}[/tex]
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.