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Sagot :

konrad509
[tex](-2)^3=-8\\ \left(\frac{3}{4}\right)^2=\frac{9}{16}[/tex]
[tex](-2)^3=(-2)\times(-2)\times(-2)=-8\\\\\\\left(\frac{3}{4}\right)^2=\frac{3^2}{4^2}=\frac{3\times3}{4\times4}=\frac{9}{16}[/tex]
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