Answered

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Solve.
If a=5 , b=6, and c=7 . then a+b+(c)(1/c) =

Sagot :

[tex]a+b+(c)(\frac{1}{c})=a+b+1\\\\a=5;\ b=6;\ c=7\ then:\\\\5+6+1=\fbox{12}[/tex]
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