Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
[tex]f(x)+g(x)=x^3+2x^2+3x^2-1=x^3+5x^2-1\\
D:x\in\mathbb{R}[/tex]
[tex]f(x)-g(x)=x^3+2x^2-(3x^2-1)=x^3+2x^2-3x^2+1=x^3-x^2+1\\ D:x\in\mathbb{R}[/tex]
[tex]f(x)\cdotg(x)=(x^3+2x^2)(3x^2-1)=3x^5-x^3+6x^4-2x^2=\\ 3x^5+6x^4-x^3-2x^2\\ D:x\in\mathbb{R}[/tex]
[tex]\frac{f(x)}{g(x)}=\frac{x^3+2x^2}{3x^2-1}\\ 3x^2-1\not=0\\ 3x^2\not=1\\ x^2\not=\frac{1}{3}\\ x\not =-\frac{\sqrt3}{3} \wedge x\not =\frac{\sqrt3}{3}\\ D:x\in(-\infty,-\frac{\sqrt3}{3} )\cup(\frac{\sqrt3}{3} ,\infty) [/tex]
[tex]f(x)-g(x)=x^3+2x^2-(3x^2-1)=x^3+2x^2-3x^2+1=x^3-x^2+1\\ D:x\in\mathbb{R}[/tex]
[tex]f(x)\cdotg(x)=(x^3+2x^2)(3x^2-1)=3x^5-x^3+6x^4-2x^2=\\ 3x^5+6x^4-x^3-2x^2\\ D:x\in\mathbb{R}[/tex]
[tex]\frac{f(x)}{g(x)}=\frac{x^3+2x^2}{3x^2-1}\\ 3x^2-1\not=0\\ 3x^2\not=1\\ x^2\not=\frac{1}{3}\\ x\not =-\frac{\sqrt3}{3} \wedge x\not =\frac{\sqrt3}{3}\\ D:x\in(-\infty,-\frac{\sqrt3}{3} )\cup(\frac{\sqrt3}{3} ,\infty) [/tex]
The answers are in the attachments below. Please open them up in a new window to see them in full.
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.