Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
[tex](-5+3i)\cdot(1-2i)\\\\=-5+10i+3i-6i^2\\\\=-5+13i-6(-1)\\\\=-5+13i+6\\\\=\boxed{1+13i}[/tex]
[tex]i=\sqrt{-1}\to i^2=-1[/tex]
[tex]i=\sqrt{-1}\to i^2=-1[/tex]
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.