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Sagot :

[tex]x-\frac{1}{6}=8\frac{2}{3}\\x=\frac{26}{3}+\frac{1}{6}\\ x=\frac{52}{6}+\frac{1}{6}\\ x=\frac{53}{6} [/tex]
8 2/3= 26/3

x-1/6=26/3  we bring to the same denominator

6x-1=52

6x=52+1

6x=53

x= 53/6