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Suppose that x and y are related by the equation 2x^2-y^2=5 and use implicit differentation to determine dy/dx.


Sagot :

AL2006
2x^2 - y^2 = 5

Differentiate:

4x - 2y dy/dx = 0

Add  2y dy/dx  to each side:

4x = 2y dy/dx

Divide each side by 2y and simplify :

2x/y = dy/dx
Answer is in the attachment below. Open it up in a new window to see it in full.
View image Аноним