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solve (answer please) n-8+n=1-4n

Sagot :

eah
n-8+n=1-4n
2n-8=1-4n
2n+4n=1+8
6n=9
n=9/6
n=3/2
[tex]n-8+n=1-4n\\\\2n-8=1-4n\ \ \ \ \ |add\ 8\ to\ both\ sides\\\\2n=9-4n\ \ \ \ \ |add\ 4n\ to\ both\ sides\\\\6n=9\ \ \ \ \ \ |divide\ both\ sides\ by\ 6\\\\n=\frac{9}{6}\ \ \ \ \ |divide\ a\ numerator\ and\ a\ denominator\ by\ 3\\\\n=\frac{3}{2}\\\\\boxed{n=1\frac{1}{2}}[/tex]
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