At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Treat the surface of the water as 0. The initial height of the weight was 4 ft above the surface of the water, therefore making it have an initial height of +4. If it travels 12 ft downward to hit the bottom of the pool, that means its height decreased by 12, so its falling is -12. To calculate the depth of the pool, use initial height minus drop distance, so 4 - 12. The depth of the pool is 8 ft.
Explanation:
Let 0 be the surface of the water.
The height 4 feet above the surface would be +4.
A 12-foot drop would be -12.
Together, this would be 4+(-12) = -8. This means the bottom of the pool is 8 feet below the surface; it means that the pool is 8 feet deep.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.