Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

really dont know what to do ..

Really Dont Know What To Do class=

Sagot :

konrad509
[tex](x+9)^2=(x+1)^2+(x+5)^2\\ x^2+18x+81=x^2+2x+1+x^2+10x+25\\ x^2-6x-55=0\\ x^2+5x-11x-55=0\\ x(x+5)-11(x+5)=0\\ (x-11)(x+5)=0\\ x=11 \vee x=-5\\\\ |AC|=x+9=11+9=20[/tex]
[tex]This\ question\ is\ illogical.\\\\If\ \Delta ABC\simeq\Delta DE F\ and\\\Delta ABC\ and\ \Delta DE F\ are\ rectangular\ triangle,\ then:\\\\\frac{|AB|}{|BC|}=\frac{|DE|}{|EF|}\\\\If\ m\angle D=60^o\ then\ m\angle A=60^o.\\The\ triangle\ 30^o;60^o;90^o\ has\ the\ relation\ between\ the\ sides\\(look\ at\ the\ picture).[/tex]

[tex]\frac{|DE|\sqrt3}{2}=12\ \ \ \ \ |multiply\ both\ sides\ by\ 2\\|DE|\sqrt3=24\ \ \ \ |multiply\ both\ sides\ by\ \sqrt3\\3|DE|=24\sqrt3\ \ \ \ |divide\ both\ sides\ by\ 3\\|DE|=8\sqrt3\Rightarrow|DF|=2\times8\sqrt3=16\sqrt3\\\\\Delta ABC:\\x+9=2(x+1)\\x+9=2x+2\\x-2x=2-9\\-x=-7\\\boxed{x=7}\\\\|AC|=x+9=7+9=\fbox{16};\\|AB|=x+1=7+1=\fbox8;\\|BC|=x+5=7+5=\fbox{12}\\\\Angles\ of\ \Delta ABC:30^o;\ 60^o;\ 90^o,\ then:[/tex]

[tex]|BC|=\frac{|AC|\sqrt3}{2}\\\\|BC|=\fbox{12}\\\\\frac{|AC|\sqrt3}{2}=\frac{16\sqrt3}{2}=\boxed{8\sqrt2}\\\\12\neq8\sqrt2[/tex]


[tex]If\ use\ Pythagoras\ theorem\ like\ Konrad:\ x=11\\\\|AC|=20\ and\ |AB|=11+1=12\\\\|AC|=2|AB|\to20=2\times12-FALSE...[/tex]
View image Аноним
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.