Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Solve 2x2 + 12x − 14 = 0 by completing the square.

Sagot :

[tex]2x^2+12x-14=0\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2+6x-7=0\\\\x^2+2x\cdot3=7\ \ \ \ |add\ 3^2\ to\ both\ sides\\\\x^2+2x\cdot3+3^2=7+3^2\\\\(x+3)^2=7+9\\\\(x+3)^2=16\iff x+3=-\sqrt{16}\ or\ x+3=\sqrt{16}\\\\x+3=-4\ or\ x+3=4\\\\x=-4-3\ or\ x=4-3\\\\\boxed{x=-7\ or\ x=1}[/tex]
View image Аноним
kate200468
[tex] 2x^2 + 12x-14 = 0\\2(x^2+6x-7)=0\ /:2\\x^2+6x+9-16=0\\x^2+6x+9=16\\(x-3)^2=4^2\\x-3=4\ \ \ or\ \ \ x-3=-4\\x=7\ \ \ \ \ \ \ \ \ or\ \ \ x=-1\\\\Ans.\ x=7\ or\ x=-1[/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.