Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

express 4-3i/(1+i)(2-3i) in the a+bi form

Sagot :

[tex]\frac{4-3i}{(1+i)(2-3i)}=\frac{4-3i}{2-3i+2i-3i^2}=\frac{4-3i}{2-i+3}=\frac{4-3i}{5-i}\times\frac{5+i}{5+i}=\frac{20+4i-15i-3i^2}{5^2-i^2}\\\\=\frac{20-11i+3}{25+1}=\frac{23-11i}{26}=\frac{23}{26}-\frac{11}{26}i[/tex]
View image Аноним
kate200468
[tex]4- \frac{\big{3i}}{\big{(1+i)(2-3i)}} =4- \frac{\big{3i}}{\big{2-3i+2i-3\cdot(-1)}} =\\\\=4- \frac{\big{3i(5+i)}}{\big{(5-i)\cdot(5+i)}} =4- \frac{\big{15i+3\cdot(-1)}}{\big{25-(-1)}} =\\\\=4- \frac{\big{15i-3}}{\big{26}} =4- \frac{\big{15i}}{\big{26}}+\frac{\big{3}}{\big{26}}=4\frac{\big{3}}{\big{26}}- \frac{\big{15}}{\big{26}}i[/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.