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Points A, B and C are collinear. Point B is between Point A and Point C. Find the length of AB if BC=x+11, AC=16, and AB=x+5

Sagot :

AB + BC = AC

(x + 5) + (x +11) = 16

2x + 16 = 16

2x = 0

x = 0

thus:

AB = x + 5 = 0 + 5 = 5
BC = x + 11= 0 + 11 = 11
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