CathleenMins
Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

What is the acceleration of a 9.6-kg rock if gravity pulls it downward, but air resistance pushes upward with a force of 2.8 N?


Sagot :

OK, so the downward force on the rock is mg (force of g) - 2.8N (force in opposite direction). since mg (9.6 kg*9.8 m/s^2)= 94.08 N, then mg-2.8= 91.28 N. That is your net force on the rock (or total force). And, since f=ma, a= f/m.
so, a= 91.28 N / 9.6 kg = 9.5 m/s^2.(final answer)
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.