Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Find x so the distance between (x,2) and (1,5) is 13.

Sagot :

[tex]A(x_1;\ y_1);\ B(x_2;\ y_2)\\\\|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\----------------\\\sqrt{(1-x)^2+(5-2)^2}=13\\(1-x)^2+3^2=169\\(1-x)^2=169-9\\(1-x)^2=160\\1-x=\pm\sqrt{160}\\-x=\pm\sqrt{16\times10}-1\\-x=\pm4\sqrt{10}-1\\\boxed{x=1\pm4\sqrt{10}}[/tex]


[tex]\sqrt{(1-x)^2+(5-2)^2}=\sqrt{13}\\(1-x)^2+3^2=13\\(1-x)^2=13-9\\(1-x)^2=4\\1-x=\pm\sqrt4\\-x=\pm2-1\\-x=-2-1\ or\ -x=2-1\\-x=-3\ or\ -x=1\\\boxed{x=3\ or\ x=-1}[/tex]
View image Аноним
View image Аноним
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.