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f(x)= 3x OVER x+1 and g(x) =x^2-1 find formula for f(g(x))

Sagot :

[tex]f(g(x))=\frac{3(x^2-1)}{x^2-1+1}=\frac{3x^2-3}{x^2}=3-\frac{3}{x^2}[/tex]
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