Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

x=square root of 880-8x

Sagot :

konrad509
[tex]x=\sqrt{880-8x}\\ D:880-8x\geq0 \wedge x\geq0\\ D:8x\leq880 \wedge x\geq0\\ D:x\leq 110 \wedge x\geq0\\ D:x\in\langle0,110\rangle\\ x^2=880-8x\\ x^2+8x-880=0\\ x^2+8x+16-896=0\\ (x+4)^2=896\\ x+4=8\sqrt{14} \vee x+4=-8\sqrt{14}\\ x=-4+8\sqrt{14} \vee x=-4-8\sqrt{14}\\ \\ x=-4-8\sqrt{14}\not \in D \Rightarrow \boxed{x=-4+8\sqrt{14}}[/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.