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Sagot :
The percent yield : 95%
Further explanation
Given
Reaction
2H₂+O₂ ⇒2H₂O
Required
The percent yield
Solution
mol of Hydrogen(as a limiting reactant) :
[tex]\tt \dfrac{100}{2}=50[/tex]
mol H₂O based on H₂ , and from equation mol ratio H₂:H₂O=2 : 2, so mol H₂O = 50
Mass of water(theoretical yield) :
[tex]\tt mass=50\times 18=900~g[/tex]
[tex]\tt \%yield=\dfrac{860}{900}\times 100\%=95\%[/tex]
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