Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

A person invests 3000 dollars in a bank. The bank pays 4.25% interest compounded semi-annually. To the nearest tenth of a year, how long must the person leave the money in the bank until it reaches 5600 dollars?

Sagot :

Answer:

The person must leave the money for approximately 14.8 years.

Step-by-step explanation:

This can be calculated using the formula for calculating the future value as follows:

FV = PV * (1 + r)^n …………………………………. (1)

Where;

FV = Future value of the investment = 5600

PV = Present value of the investment = 3000

r = semiannual interest rate = 4.25% / 2 = 0.0425 / 2 = 0.02125

n = number of semiannuals = ?

Substitute the values into equation (1) and solve for n, we have:

5600 = 3000 * (1 + 0.02125)^n

5600 / 3000 = 1.02125^n

1.02125^n = 1.86666666666667

Loglinearizing both sides, we have:

nlog1.02125 = log1.86666666666667

n = log1.86666666666667 / log1.02125

n = 0.271066772286539 / 0.0091320695404719

n = 29.6829509548973

Since n is number of semiannuals, we divide the answer by 2 obtain the number of years as follows:

Number of years = 29.6829509548973 / 2 = 14.8414754774487

Rounding to the nearest tenth of year, we have:

Number of years = 14.8

Therefore, the person must leave the money for approximately 14.8 years.