A geneticist crossed pure breeding black mice with pure breeding brown mice. All the mice in the F1 generation had black coats. When these mice were crossed, they yielded 961 black coated mice and 317 brown coated mice.

Fill in the new combinations of alleles in the F2 generation.

Question

07-01-2021
Biology

Answered

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A geneticist crossed pure breeding black mice with pure breeding brown mice. All the mice in the F1 generation had black coats. When these mice were crossed, they yielded 961 black coated mice and 317 brown coated mice.

Fill in the new combinations of alleles in the F2 generation.

Sagot :

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Histrionicus Histrionicus · Answer 1 · 2021-01-11T19:23:57-05:00

Answer:

The correct answer is - the brown allele is not independent from the black allele and disappears in the F1 generation.

Explanation:

IN this question it is given that there is a cross between pure black and pure brown breed and the F1 generation has all-black coat offspring and their self cross produced 961 black and 317 brown.

The black coat offspring is three times than the brown coat offspring in F2 generation which means they have 3:1 ratio that comes in the self cross of heterozygous only there for the F1 generation black coat offspring have the heterozygous genotype for the trait,

Thus, the brown allele is not independent of the black allele and disappears in the F1 generation.

A geneticist crossed pure breeding black mice with pure breeding brown mice. All the mice in the F1 generation had black coats. When these mice were crossed, they yielded 961 black coated mice and 317 brown coated mice. Fill in the new combinations of alleles in the F2 generation.

Sagot :

Other Questions

A geneticist crossed pure breeding black mice with pure breeding brown mice. All the mice in the F1 generation had black coats. When these mice were crossed, they yielded 961 black coated mice and 317 brown coated mice.

Fill in the new combinations of alleles in the F2 generation.